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I am stuck on figuring out what form the bytes are in when they're read? I created a buffer of type char and I get one result when I read the bytes in. Then I created a buffer of type int and I get a different result when reading over those same bytes.

I am looking for a data type to store the bytes as hexadecimal.

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    – i_am_david
    Jul 30, 2015 at 4:14

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Unsigned char works, so does uint8_t.

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  • may i ask why int does not work? all these variable types store integers. and int has larger range of value than uint_8t or unsigned char. so int has these numbers in its range too. i'm a little bit confused.
    – henry morgan
    Oct 1, 2017 at 22:20

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