0

For speller.c, you can't pass a pointer to the root node (I'm using a trie) to check(), size(), and unload(). And I couldn't create a global root node in dictionary.c

error: initializer element is not a compile-time constant

So, how do they know what to check, measure and unload?

Improve this question
5
  • How do you initialize the pointer when declaring it as a global variable?
    – kzidane ♦
    Jun 16, 2014 at 13:36
  • There's this function, called getNode() I created, which returns a pointer to an empty node. So, in dictionary.c, I initialized struct node* root = getNode(); outside the functions, so it will be accessible to all functions.
    – Pranav Ballaney
    Jun 16, 2014 at 15:00
  • You may try initializing it to NULL initially like struct node* = NULL;
    – kzidane ♦
    Jun 16, 2014 at 15:01
  • struct node* is a data type! How can I initialize a data type to NULL?
    – Pranav Ballaney
    Jun 16, 2014 at 15:12
  • I'm sorry I meant struct node* root = NULL!
    – kzidane ♦
    Jun 16, 2014 at 18:02

1 Answer 1

Reset to default
2

So that error was being caused because the function getNode() was being used outside another function. Turns out, clang doesn't like that.

So I did the following:

node root_node;
node* root = &root_node;

That fixed it!

Improve this answer
1
  • Did you add those lines to dictionary.c, outside of the load function?
    – Jesse
    Sep 21, 2014 at 11:30

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .