using modf in greedy

Question

I'm getting a compilation error using fmod to split the int from the remainder.
error: passing 'int *' to parameter of incompatible type 'double'

Here's the code:

 // definitions

float da, F;
int I, F2, Q1;

while (da > 0.00)           
{
    F = modf (da, &I);
    F2 = round (F * 100);
    Q1 = I / .25;  
}

printf("Integer %d and rounded remainder %d", I, Q1)

Answer 1

floats and doubles are not precise. Better work with ints! After you receive the input from the user, convert it to cents and round it to the nearest integer using a function like round() from the math library immediately!

As for your compilation error, modf() accepts a double and a pointer to a double (aka a double *). You're passing a float and a pointer to an int (aka int *) instead.