Can't break out of while loop in python

Question

def main():
    x = 0
    while x not in range (1,23):
        getheight()
        if x in range (1,23):
            break
    for i in range (x):
        for j in range (x - j):
            print (" ", end="")
        for j in range (x):
            print ("#", end="")
        print ("  ", end="")
        for j in range (x):
            print ("#", end="")
        "\n"

def getheight():
    x = input("Give me a positive integer no more than 23 \n")
    return x

if __name__ == "__main__":
    main()

Answer 1

x is always 0 in the while loop. Scope. The x that gets input in the getheight function is local to the function.

If you change it to something like x = getheight(), be aware from the python doc on input():

The function then reads a line from input, converts it to a string (stripping a trailing newline),

so x is never in range (1,23)