C: Trouble with isalpha and char* - Error: expected expression

Question

I am receiving the error: expected expression with this line of code.

if(char* i in (word[i]) isalpha) {

I need to iterate over the characters[i] in a word entered by the user. First I need to check that each letter is a character.

I have modified this code in many ways, including putting isalpha first inside the brackets but always receive an error.

I have tried defining char word before the 'if' statement commences but this hasn't worked either.

I am also confused about the reason why some people use the * with char and others not. I hope someone can assist me.

Answer 1

I guess you mean if (isalpha(word[i])), with word being a char[] or char*, and i being something like an int? Could you maybe clarify your question by adding the surrounding code to your question?