I have created a series of for loops to iterate through every combination of a 4 letter long password (i j k l). I wish to enter each iteration into the crypt function but what I have been trying has not worked so far (code show below), the crypt function only acknowledges 1 of the 4 chars.
I have attempted concatenating the chars together but that does not seem to work. Any advice would be much appreciated!
Specific issue:
crypt((letters[i]letters[j]letters[k]letters[l]),"50")
Whole Code:
#include <cs50.h>
#include <cs50.h>
#include <stdio.h>
#include <unistd.h>
#include <crypt.h>
#include <string.h>
char* letters[] = {" ","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
int main(int argc, string argv[])
{
if (argc != 2)
{
printf("missing command-line argument\n");
return 1;
}
else
{
for (int i = 0; i < 5; i++)
{
for (int j = 0; j < 5; j++)
{
for (int k = 0; k < 5; k++)
{
for (int l = 0; l < 5; l++)
{
if (strcmp(argv[1],crypt((letters[i]letters[j]letters[k]letters[l]),"50")) == 0)
{
printf("Password: %s%s%s%s", letters[i],letters[j],letters[k],letters[l]);
break;
}
}
}
}
}
return 0;
}
}
error code:
pset2/crack4.c:27:61: error: expected ')'
if(strcmp(argv[1],crypt((letters[i]letters[j]letters[k]letters[l]),"50")) == 0)
^
pset2/crack4.c:27:50: note: to match this '('
if(strcmp(argv[1],crypt((letters[i]letters[j]letters[k]letters[l]),"50")) == 0)
^
1 error generated.