Pset2 initials, how to get to second word

Question

please dont laugh at me as i am totally new to programming, and on top of that maybe not very smart. I am just enjoying a lot what i am learning though i am afraid i will not be able to finish the cs50 course cause it seems to hard. Anyway, im trying to solve the initials pset2. I can get first letter of first word in printed in capital, and thats it. I can t find the logic to go to next word. At the beginning i was going with argv and argc so at least i could isolate names and get to first letter. But with int-main-void i just cant seem to do it. Here is my code, any hint would be much appreciated

#include <stdio.h>
#include <cs50.h>
#include <string.h>
#include <ctype.h>

int main(void)


{
    //get a name

    string name = get_string();
    //make sure you get a word
    if (name != NULL)
    //print First capital Firts word
    printf("%c", toupper(name[0]));

    {

    for

    //loop duration until /0ahahah i wanna get after this \0
(int i = 0;name[i] == '\0'; i++ )

{ 
  if(name[i] == ' ')

       {
    //print  0 +1  character (next after space)
    printf("%c", toupper (name[i]+1));

}

}
 printf("\n");
}}

after Blauelf suggestion

#include <stdio.h>
#include <cs50.h>
#include <string.h>
#include <ctype.h>

int main(void)


{
    //get a name

    string name = get_string();
    //make sure you get a word
    if (name != NULL)
    //print First capital Firts word
    printf("%c", toupper(name[0]));

    {

    for

    //loop duration until /0ahahah i wanna get after this \0
(int i = 0;name[i] != '\0'; i++ )

{ 
  if(name[i] == ' ')

       {
    //print  0 +1  character (next after space)
    printf("%c", toupper (name[i+1]));

}

}
 printf("\n");
}}

its working but i dont get why.It should stop after the first inputted word, aint it?

Answer 1

A few things:

Print toupper(name[0]) only if it's a letter (and not a leading space).

The condition in a for loop should be non-zero (true is non-zero for example) if you want to keep looping, so use ; name[i] != '\0'; instead of ==.

Print the character following a space (name[i + 1], not name[i] + 1) only if it is a letter and not a second space character or the null terminator.