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I'm getting an error and I can't figure out the solution to this problem. I get an error at check cs50: "input of 0.41 yields output of 4; expected "4\n", not "You typed: 0.41..."

Here is my code:

#include <stdio.h>
#include <cs50.h>
#include <math.h>

int main (void)

{

float cents;
int coins, change;

do
{
    cents = get_float ("Change: ");
} while (cents <= 0);

change = (int) roundf(cents * 100);

printf("You typed: %f\n", cents);
printf("You typed: %d\n", change);

for (coins = 0; change > 0; coins++)
{

if (change >= 25)
{
    change -= 25;
}
else if (change < 25 && change >= 10)
{
    change -= 10;
}
else if (change < 10 && change >= 5)
{
    change -= 5;
}
else
{
    change -= 1;
}
}

printf("Coins: %d\n", coins);

}

I searched for a solution to this problem but I could not find anything that worked. Thank you for your time!

1

check50 does an automated test.

This means that some program will look at your output, and tries to see whether it is the same as expected.

Actually, the specifications say:

we ask that your program’s last line of output be only the minimum number of coins possible: an integer followed by \n.

Therefore, the program looks at all your output, and checks (for this input) whether it is exactly the same as 4\n. And in your case, it isn't ...


Finally, to quote Cliff B:

If this answers your question, please click on the check mark to accept. Let's keep up on forum maintenance. ;-)

| improve this answer | |
  • Thank you for answering! I had a minor error which apparently solved the problem with check50! Not sure why it had that error, but I guess it's solved now. Side note: I forgot to add change >= 10 in dimes and that was making all the trouble -- so it seems. – Ffs Oct 23 '18 at 11:39

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