SELECT AVG(rating) FROM ratings WHERE ratings.movie_id = (SELECT id FROM movies where movies.year = 2012);
It doesnt seem to print anything.
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Sign up to join this communityYou did the hardest part, now it needs just one little improvement. If you write "ratings.movie_id = " program takes just one match. You should use "ratings.movie_id IN ", and then program takes all matches. Hope it helps. With code below output is 6.27545924967655
SELECT AVG(rating) FROM ratings WHERE movie_id IN (SELECT id FROM movies where
movies.year = 2012)