INPUT int main(void) { long long cardnumber, calc; string credit[0]; string nonnumeric; //long long calc = card number; int countcardcharacters = 0; long long c;

//user input
    credit[0]= get_string("Card number: ");
while (credit < 0);

printf("%lli\n", cardnumber);

/*checksum(long long calc);

cardnumber = long long strtoll(const char credit, &nonnumeric, 10);
calc = cardnumber;
//credit[0] = cardnumber;
//printf("%li\n", credit[0]);

if (strlen(credit[0]) == 15)
    while (credit[0][0] == 3 && (credit[0][1] == 4 || credit[0][1] == 7))
        //american express

OUTPUT clang -ggdb3 -O0 -std=c11 -Wall -Werror -Wextra -Wno-sign-compare -Wno-unused-parameter -Wno-unused-variable -Wshadow credit.c -lcrypt -lcs50 -lm -o credit credit.c:33:18: error: expected expression cardnumber = long int strtoll(const char credit, &nonnumeric, 10); ^ 1 error generated. : recipe for target 'credit' failed

  • The "types" in the man page are not literally used in the function, they indicate the type(s) that the function 1) returns, in this case long int and 2) expects as parameters. That is the proximate cause of the compile error. – DinoCoderSaurus Jul 9 at 14:39
  • i tried changing the long int to long long but it's still not compiling – Gloria Isedu Jul 9 at 16:12
  • The types are not included in the function call. A valid strtoll call would look something like num = strtoll(somestring,NULL,10). Read the man page to find out why NULL can be used for the second argument. – DinoCoderSaurus Jul 9 at 17:27
  • "credit.c:41:27: error: incompatible pointer types passing 'string [0]' to parameter of type 'const char *' [-Werror,-Wincompatible-pointer-types] cardnumber = strtoll (credit, NULL, 10); ^~~~~~ /usr/include/stdlib.h:200:54: note: passing argument to parameter '__nptr' here extern long long int strtoll (const char *__restrict __nptr," This is what I got when i tried that that's why I used 'const char' and 'long long'. but thanks for your input. – Gloria Isedu Jul 9 at 17:38
  • I've tried changing the strtoll to atoll but it still won't compile – Gloria Isedu Jul 9 at 18:33

The reason that this

cardnumber = strtoll (credit, NULL, 10)

gives this error

error: incompatible pointer types passing 'string [0]' to parameter of type 'const char *' 

is because the variable credit has been declared an array of strings with 0 members here

string credit[0];

I am inclined to think that was not the intention. Prompting the user for a string with get_string is much the same as prompting the user for an integer with get_int as would have been done in mario. Here is the example from the source code that accompanies the lecture to use as a guide.

    // get_string and printf with %s 


            string s = get_string("What's your name?\n"); 
            printf("hello, %s\n", s);
| improve this answer | |
  • thank you, I'll try again. I thought credit[0] meant it had 1 member since it starts counting from zero. – Gloria Isedu Jul 9 at 22:43
  • I tried changing it to "string credit[11]" but i got the same error message still. – Gloria Isedu Jul 9 at 22:45
  • credit should not be an array, just a plain ol' string. Added info to the answer. – DinoCoderSaurus Jul 9 at 23:22
  • oh alright, thanks – Gloria Isedu Jul 10 at 0:51

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