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Caesar problem. Keep getting error of segmentation

The follow part of code worked perfectly, while I declared variables key_num and plaintext within if{}, but since I declared them outside (cause I need to use these vars later) I get the "...
Igor Roytman's user avatar
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3 answers
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:( handles lack of argv[1] failed to execute program due to segmentation fault

if (argv[1] == NULL) { printf("Usage: ./caesar key\n"); return(1); } this is the solution before the program received the first statement validate null
ramon chacon's user avatar
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1 answer
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Debugging problem caesar cipher pset1

I need some help with my debugging for the caesar cipher. I get these errors. [image replaced with actual errors produced by the code that follows] caesar.c:25:17: error: incompatible integer to ...
Mohammed Shayan Khan's user avatar
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2 answers
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misleading description of int main(int argc, string argv[])

In pset2 description following is said about int main(int argc, string argv[]) function: 1 : Well, recall that inside of argv[0], by default, is a program’s own name Q1: How come argv[0] is by ...
Dauren Z's user avatar