`int *` is a pointer to an int, so you'll get two errors there:

    error: incompatible integer to pointer conversion initializing
          'int *' with an expression of type 'int' [-Werror,-Wint-conversion]
    int *pkk = 5646;
         ^     ~~~~
    ptr.c:6:18: error: format specifies type 'int' but the argument has type 'int *'
          [-Werror,-Wformat]
      printf("%d\n", pkk);
              ~~     ^~~

The first is saying that you can initialize a pointer with an integer value.  The second is saying that you can't print a pointer type using the `"%d"` format specifier, as that is for printing an integer.


Your char * example works fine because of how C defines a char pointer.

Pointers are covered in Weeks 4 and 5. Have you already completed those?