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you have a small typo error in the function you have written: int get_positive_int versus: int get_positive_int_

I don't think you have understood how a DO-WHILE loop works. The difference with other loops is that THIS is going to be executed at least once, regardless of the condition we impose. With this we get …

This is not to be taken literally, the circumflex accent notation ^ is a common way of representing power, and it is indeed a bitwise operator in C. …

In effect it is not an ascii value for an alphabetical character, if, however, it is not what we are trying to do, but what we want is to substitute the m character for the corresponding one of the ke …

Problematic code, but we are on the right track, two things regarding your question: else { // NO // continue copying fwrite(buffer, 512, 1, output); } …

In the current implementation of the functions of the header file cs50.h, we need at least one argument of the type char *, that is, a string, something similar to the function printf (), therefore to …

You have a "small" problem in check function, you actually go through the entire hash table without finding any match. What happens if strcasecmp () is zero? Why do you keep moving forward in the hash …

EDIT 2: You have an array of pointers, I would use char * dictionary = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"; char key[12]; //to copy the characters To use a single character w …

If you use the IDE, the easiest way is to use the make command, if not, you must use the -lcs50 option when compiling to avoid the error indicated

encrypted character, the following works: if (alphabets_upper[index] == s[i]) { int cipher = alphabets_upper[(index + key) % 26]; printf("%c" … , cipher); } if (alphabets_lower[index] == s[i]) { int cipher = alphabets_lower[(index + key) % 26]; printf("%c" …

return copyindex; The return statement has two important uses. First, the one that matters here, forces an immediate exit from the function in which it finds itself. That is, it causes the execution …

I think you complicate your program unnecessarily with calls to functions that do not clarify the code, recover can be done in a simpler way, and personally I always look for the greatest possible sim …

I honestly do not understand what your question is, but the statement is incorrect: printf (" ",(num[i]+=1)); In printf, what goes after the quotes is variable that will be printed, with the approp …

To evaluate the right side first we must put the parentheses on the right side of the identity, not the operator == itself if (counterCardLength == 15 && FindFirstTwoDigits == (34 | 37)) if (a == (1 …

What is supposed to be * card? We can not apply own operators of a pointer to a variable of integer type in this case. It seems that the compiler is interpreting this as an indirect operation of a poi …