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I'm struggling with printing the initials after the first name, I'm following the less comfortable specs, my pseudocode;

//prompt user for name and store as string

//convert strlen to an integer

//print first character using toupper for lower case inputs

//using a for loop, print the char directly after a space, again using toupper

My code prints the first character just fine but no following characters, I can assume that there are no extra spaces, the for loop is as follows;

    for ( int j = 0; j <= i; j++ )

    {
        if ( (char)s[j] == ' ')
        printf("%c", toupper( s[j + 1] ) );
    }

It compiles just fine so it's not a syntax error, any help would be greatly appreciated as I'm getting to the stage of just trying different wording which doesn't really help me much as far as learning goes.

Cheers

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  • How is i being declared and computed? Are there any if clauses before this loop that would possibly skip it?
    – DinoCoderSaurus
    Commented Feb 13, 2017 at 18:50
  • You were absolutely spot on! I had declared i unknowingly after setting it to strlen as part of my first initial as follows; printf("%c", toupper( s[ i = 0 ]) ); when I can just use s[0]. I didn't realise this would over ride the pre assigned value for i. Thank you very much :)
    – Thomas Forrest
    Commented Feb 13, 2017 at 18:58
  • Great! Suggest you make that an answer, instead of (or in addition to) a comment. That might help others facing a similar problem. Then, in 2 days time, you could accept it as the answer.
    – DinoCoderSaurus
    Commented Feb 13, 2017 at 20:19

1 Answer 1

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As DinoCoderSaurus helpfully pointed out in the comments, I was trying to use the integer i believing it to have the value of the string length, but I had actually set it to 0 in an earlier line of code, using the debug tool properly would have shown me this as I went through line by line.

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